LeetCode - Array Nesting

Question Definition

A zero-indexed array A of length N contains all integers from 0 to N-1. Find and return the longest length of set S, where S[i] = {A[i], A[A[i]], A[A[A[i]]], ... } subjected to the rule below.

Suppose the first element in S starts with the selection of element A[i] of index = i, the next element in S should be A[A[i]], and then A[A[A[i]]]… By that analogy, we stop adding right before a duplicate element occurs in S.

Example 1:

Input: A = [5,4,0,3,1,6,2]
Output: 6
Explanation:
A[0] = 5, A[1] = 4, A[2] = 0, A[3] = 3, A[4] = 1, A[5] = 6, A[6] = 2.

One of the longest S[K]:
S[0] = {A[0], A[5], A[6], A[2]} = {5, 6, 2, 0}

Note:

  1. N is an integer within the range [1, 20,000].
  2. The elements of A are all distinct.
  3. Each element of A is an integer within the range [0, N-1].

    My Java Solution

    public int arrayNesting(int[] nums) {
     int max = 0;
     for(int i = 0; i < nums.length; i++){
         if(nums[i] >= 0){
             int cur = 0;
             int index = nums[i];
             while(true){
                 int temp = nums[index];
                 nums[index] = nums[index] == 0 ? -1 : -nums[index];
                 index = temp;
                 if(index >= 0)
                     cur++;
                 else break;
             }
             if(cur > max)
                 max = cur;
         }
     }
     return max;
    }
    

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