Question Definition
A zero-indexed array A of length N contains all integers from 0 to N-1. Find and return the longest length of set S, where S[i] = {A[i], A[A[i]], A[A[A[i]]], ... }
subjected to the rule below.
Suppose the first element in S starts with the selection of element A[i]
of index = i, the next element in S should be A[A[i]]
, and then A[A[A[i]]]…
By that analogy, we stop adding right before a duplicate element occurs in S.
Example 1:
Input: A = [5,4,0,3,1,6,2]
Output: 6
Explanation:
A[0] = 5, A[1] = 4, A[2] = 0, A[3] = 3, A[4] = 1, A[5] = 6, A[6] = 2.
One of the longest S[K]:
S[0] = {A[0], A[5], A[6], A[2]} = {5, 6, 2, 0}
Note:
- N is an integer within the range [1, 20,000].
- The elements of A are all distinct.
- Each element of A is an integer within the range [0, N-1].
My Java Solution
public int arrayNesting(int[] nums) { int max = 0; for(int i = 0; i < nums.length; i++){ if(nums[i] >= 0){ int cur = 0; int index = nums[i]; while(true){ int temp = nums[index]; nums[index] = nums[index] == 0 ? -1 : -nums[index]; index = temp; if(index >= 0) cur++; else break; } if(cur > max) max = cur; } } return max; }
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