LeetCode - Product of Array Except Self

Question Definition

Given an array of n integers where n > 1, nums, return an array output such that output[i] is equal to the product of all the elements of nums except nums[i].

Solve it without division and in O(n).

For example, given [1,2,3,4], return [24,12,8,6].

Follow up:

Could you solve it with constant space complexity? (Note: The output array does not count as extra space for the purpose of space complexity analysis.)

Java Solution

public int[] productExceptSelf(int[] nums) {
    int[] result = new int[nums.length];
    result[0] = 1;
    for(int i = 1; i < nums.length; i++){
        result[i] = result[i - 1] * nums[i - 1];
    }
    int right = 1;
    for(int i = nums.length - 1; i >= 0; i--){
        result[i] = result[i] * right;
        right *= nums[i];
    }

    return result;
}