Question Definition
Given an array of integers and an integer k, you need to find the total number of continuous subarrays whose sum equals to k.
Example 1:
Input:nums = [1,1,1], k = 2
Output: 2
Note:
- The length of the array is in range
[1, 20,000]
. - The range of numbers in the array is
[-1000, 1000]
and the range of the integer k is[-1e7, 1e7]
.My Java Solution
public int subarraySum(int[] nums, int k) { int[] sum = new int[nums.length + 1]; for(int i = 1; i <= nums.length; i++) sum[i] = sum[i - 1] + nums[i - 1]; int count = 0; for(int i = 0; i <= nums.length; i++){ for(int j = i + 1; j <= nums.length; j++){ if(sum[j] - sum[i] == k) count++; } } return count; }
Best Java Solution
public int subarraySum(int[] nums, int k) { int sum = 0, result = 0; Map<Integer, Integer> preSum = new HashMap<>(); preSum.put(0, 1); for (int i = 0; i < nums.length; i++) { sum += nums[i]; if (preSum.containsKey(sum - k)) { result += preSum.get(sum - k); } preSum.put(sum, preSum.getOrDefault(sum, 0) + 1); } return result; }
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