LeetCode - Add Two Numbers II

Question Definition

You are given two non-empty linked lists representing two non-negative integers. The most significant digit comes first and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

You may assume the two numbers do not contain any leading zero, except the number 0 itself. Follow up: What if you cannot modify the input lists? In other words, reversing the lists is not allowed.

Example:

Input: (7 -> 2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 8 -> 0 -> 7

Java Solution

public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
    Stack<Integer> s1 = new Stack<Integer>();
    Stack<Integer> s2 = new Stack<Integer>();

    while(l1 != null) {
        s1.push(l1.val);
        l1 = l1.next;
    };
    while(l2 != null) {
        s2.push(l2.val);
        l2 = l2.next;
    }

    int sum = 0;
    ListNode list = new ListNode(0);
    while (!s1.empty() || !s2.empty()) {
        if (!s1.empty()) sum += s1.pop();
        if (!s2.empty()) sum += s2.pop();
        list.val = sum % 10;
        ListNode head = new ListNode(sum / 10);
        head.next = list;
        list = head;
        sum /= 10;
    }

    return list.val == 0 ? list.next : list;
}

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