Question Definition
Given a non-empty string containing an out-of-order English representation of digits 0-9, output the digits in ascending order. Note:
- Input contains only lowercase English letters.
- Input is guaranteed to be valid and can be transformed to its original digits. That means invalid inputs such as “abc” or “zerone” are not permitted.
- Input length is less than 50,000.
Example 1:
Input: "owoztneoer"
Output: "012"
Example 2:
Input: "fviefuro"
Output: "45"
Java Solution
public String originalDigits(String s) {
int[] count = new int[10];
for (int i = 0; i < s.length(); i++){
char c = s.charAt(i);
if (c == 'z') count[0]++;
if (c == 'w') count[2]++;
if (c == 'x') count[6]++;
if (c == 's') count[7]++; //7-6
if (c == 'g') count[8]++;
if (c == 'u') count[4]++;
if (c == 'f') count[5]++; //5-4
if (c == 'h') count[3]++; //3-8
if (c == 'i') count[9]++; //9-8-5-6
if (c == 'o') count[1]++; //1-0-2-4
}
count[7] -= count[6];
count[5] -= count[4];
count[3] -= count[8];
count[9] = count[9] - count[8] - count[5] - count[6];
count[1] = count[1] - count[0] - count[2] - count[4];
StringBuilder sb = new StringBuilder();
for (int i = 0; i <= 9; i++){
for (int j = 0; j < count[i]; j++){
sb.append(i);
}
}
return sb.toString();
}
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