LeetCode - Queue Reconstruction by Height

Question Definition

Suppose you have a random list of people standing in a queue. Each person is described by a pair of integers (h, k), where h is the height of the person and k is the number of people in front of this person who have a height greater than or equal to h. Write an algorithm to reconstruct the queue.

Note: The number of people is less than 1,100.

Example

Input:
[[7,0], [4,4], [7,1], [5,0], [6,1], [5,2]]

Output:
[[5,0], [7,0], [5,2], [6,1], [4,4], [7,1]]

Java Solution

public int[][] reconstructQueue(int[][] people) {
    PriorityQueue<int[]> que = new PriorityQueue<>((a,b)->a[0] == b[0] ? a[1] - b[1] : b[0] - a[0]);

    for(int[] p : people)
        que.offer(p);

    List<int[]> list = new LinkedList<>();
    while(!que.isEmpty()){
        int[] temp = que.poll();
        list.add(temp[1], temp);
    }
    return list.toArray(new int[list.size()][2]);
}

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