Question Definition
Given a matrix of M x N elements (M rows, N columns), return all elements of the matrix in diagonal order as shown in the below image.
Example:
Input:
[
[ 1, 2, 3 ],
[ 4, 5, 6 ],
[ 7, 8, 9 ]
]
Output: [1,2,4,7,5,3,6,8,9]
Explanation:
Note:
- The total number of elements of the given matrix will not exceed 10,000.
Java Solution
public int[] findDiagonalOrder(int[][] matrix) { if (matrix.length == 0) return new int[0]; int r = 0, c = 0, m = matrix.length, n = matrix[0].length, arr[] = new int[m * n]; for (int i = 0; i < arr.length; i++) { arr[i] = matrix[r][c]; if ((r + c) % 2 == 0) { // moving up if (c == n - 1) { r++; } else if (r == 0) { c++; } else { r--; c++; } } else { // moving down if (r == m - 1) { c++; } else if (c == 0) { r++; } else { r++; c--; } } } return arr; }
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