LeetCode - Linked List Cycle II

Question Definition

Given a linked list, return the node where the cycle begins. If there is no cycle, return null. Note: Do not modify the linked list.

Follow up: Can you solve it without using extra space?

Java Solution

public ListNode detectCycle(ListNode head) {
    if(head == null || head.next == null)
        return null;
    ListNode slow = head;
    ListNode fast = head;
    while(fast != null && fast.next != null){
        slow = slow.next;
        fast = fast.next.next;
        if(slow == fast)
            break;
    }
    if(fast != null && fast.next != null){
        slow = head;
        while (slow != fast) {
            slow = slow.next;
            fast = fast.next;
        }
        return fast;
    }else
        return null;
}

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