Question Definition
Additive number is a string whose digits can form additive sequence.
A valid additive sequence should contain at least three numbers. Except for the first two numbers, each subsequent number in the sequence must be the sum of the preceding two.
For example: “112358” is an additive number because the digits can form an additive sequence: 1, 1, 2, 3, 5, 8.
1 + 1 = 2, 1 + 2 = 3, 2 + 3 = 5, 3 + 5 = 8
“199100199” is also an additive number, the additive sequence is: 1, 99, 100, 199.
1 + 99 = 100, 99 + 100 = 199
**Note: **Numbers in the additive sequence cannot have leading zeros, so sequence 1, 2, 03 or 1, 02, 3 is invalid.
Given a string containing only digits ‘0’-‘9’, write a function to determine if it’s an additive number.
Follow up: How would you handle overflow for very large input integers?
Java Solution
class Solution {
public boolean isAdditiveNumber(String num) {
if(num.length() == 0) return true;
if(num.length() < 3) return false;
for(int i = 1; i < num.length(); i++){
if(i > 1 && num.startsWith("0")) break;
double x1 = Double.parseDouble(num.substring(0, i));
if(isAdditiveNumber(num.substring(i), x1))
return true;
}
return false;
}
public boolean isAdditiveNumber(String num, double x1) {
for(int j = 1; j < num.length(); j++){
if(j > 1 && num.startsWith("0")) break;
double x2 = Double.parseDouble(num.substring(0, j));
String next = String.format("%.0f", x1 + x2);
if(num.startsWith(next, j) && (next.equals(num.substring(j)) || isAdditiveNumber(num.substring(j), x2))){
return true;
}
}
return false;
}
}
Comments